If it's not what You are looking for type in the equation solver your own equation and let us solve it.
Simplifying 2k4 = 0 Solving 2k4 = 0 Solving for variable 'k'. Move all terms containing k to the left, all other terms to the right. Divide each side by '2'. k4 = 0 Simplifying k4 = 0 The solution to this equation could not be determined.
| 0=23(x+y)(4y)(y^2) | | -1/6t4 | | (23-2x)(11.5-2x)(15x)=0 | | 0=23(x+y)(4y)(y) | | 5y+3x-5=8fory | | x^2+y^2-z^2=1 | | 1/5=25/x | | (X^2)-16)/2x)(6/((3x)-(12 | | 2/3b=8/7 | | 2/3b=8/8 | | 4AB+5AB= | | x^3=240 | | -14m-15=95 | | 2(x-1)-(y-7)=13 | | x^2+y^2=2z | | -4m-15=95 | | (6a+3b-5)+(8b-6)= | | 0=-32x^2+2025x+162000 | | 17-8+x=8+8-1 | | 9y-3x+6=0 | | a=1/2bc | | t=-8 | | 56=6 | | 0=-32x^2+2025x+364500 | | X/x=1.65 | | 2(x-3)=9-5(2x+1) | | 12x-(3/2)x^2=0 | | 7x=3/6 | | 0.125x+8=-4 | | 12x-1.5x^2=0 | | 13-16/(5-3)*3= | | 4a-3/2a-3 |